Base | Representation |
---|---|
bin | 110001011000011110… |
… | …100000110111110001 |
3 | 12001212100000100212012 |
4 | 301120132200313301 |
5 | 1332043121022041 |
6 | 40205304212305 |
7 | 3554661401501 |
oct | 613036406761 |
9 | 161770010765 |
10 | 53024001521 |
11 | 2053a737167 |
12 | a33976a095 |
13 | 5000408b3a |
14 | 27d01c3a01 |
15 | 15a50ca3eb |
hex | c587a0df1 |
53024001521 has 8 divisors (see below), whose sum is σ = 56585134080. Its totient is φ = 49511988288.
The previous prime is 53024001473. The next prime is 53024001523. The reversal of 53024001521 is 12510042035.
53024001521 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53024001521 - 214 = 53023985137 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53024001523) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12277601 + ... + 12281918.
It is an arithmetic number, because the mean of its divisors is an integer number (7073141760).
Almost surely, 253024001521 is an apocalyptic number.
It is an amenable number.
53024001521 is a deficient number, since it is larger than the sum of its proper divisors (3561132559).
53024001521 is a wasteful number, since it uses less digits than its factorization.
53024001521 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24559663.
The product of its (nonzero) digits is 1200, while the sum is 23.
Adding to 53024001521 its reverse (12510042035), we get a palindrome (65534043556).
The spelling of 53024001521 in words is "fifty-three billion, twenty-four million, one thousand, five hundred twenty-one".
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