Base | Representation |
---|---|
bin | 110001011000011110… |
… | …100011001101111101 |
3 | 12001212100000212001012 |
4 | 301120132203031331 |
5 | 1332043121324013 |
6 | 40205304325005 |
7 | 3554661441512 |
oct | 613036431575 |
9 | 161770025035 |
10 | 53024011133 |
11 | 2053a743405 |
12 | a339773765 |
13 | 5000410322 |
14 | 27d01c7309 |
15 | 15a50cd1a8 |
hex | c587a337d |
53024011133 has 4 divisors (see below), whose sum is σ = 54852425340. Its totient is φ = 51195596928.
The previous prime is 53024011021. The next prime is 53024011153. The reversal of 53024011133 is 33111042035.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 36671484004 + 16352527129 = 191498^2 + 127877^2 .
It is a cyclic number.
It is not a de Polignac number, because 53024011133 - 232 = 48729043837 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53024011099 and 53024011108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53024011153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 914207060 + ... + 914207117.
It is an arithmetic number, because the mean of its divisors is an integer number (13713106335).
Almost surely, 253024011133 is an apocalyptic number.
It is an amenable number.
53024011133 is a deficient number, since it is larger than the sum of its proper divisors (1828414207).
53024011133 is a wasteful number, since it uses less digits than its factorization.
53024011133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1828414206.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 53024011133 its reverse (33111042035), we get a palindrome (86135053168).
The spelling of 53024011133 in words is "fifty-three billion, twenty-four million, eleven thousand, one hundred thirty-three".
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