Base | Representation |
---|---|
bin | 110001011000011111… |
… | …000000111110001101 |
3 | 12001212100021001012222 |
4 | 301120133000332031 |
5 | 1332043134224010 |
6 | 40205311105125 |
7 | 3554662460024 |
oct | 613037007615 |
9 | 161770231188 |
10 | 53024133005 |
11 | 2053a816a28 |
12 | a3398121a5 |
13 | 500045393c |
14 | 27d02198bb |
15 | 15a5104355 |
hex | c587c0f8d |
53024133005 has 8 divisors (see below), whose sum is σ = 63631604472. Its totient is φ = 42417543168.
The previous prime is 53024132977. The next prime is 53024133011. The reversal of 53024133005 is 50033142035.
53024133005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 3217498729 + 49806634276 = 56723^2 + 223174^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53024133005 - 210 = 53024131981 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79952 + ... + 335321.
It is an arithmetic number, because the mean of its divisors is an integer number (7953950559).
Almost surely, 253024133005 is an apocalyptic number.
It is an amenable number.
53024133005 is a deficient number, since it is larger than the sum of its proper divisors (10607471467).
53024133005 is a wasteful number, since it uses less digits than its factorization.
53024133005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 440815.
The product of its (nonzero) digits is 5400, while the sum is 26.
The spelling of 53024133005 in words is "fifty-three billion, twenty-four million, one hundred thirty-three thousand, five".
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