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5302425404513 = 14473664426679
BaseRepresentation
bin100110100101001000100…
…1011101100010001100001
3200202220111010212110200002
41031022101023230101201
51143333331400421023
615135522310305345
71055042021166626
oct115122113542141
920686433773602
105302425404513
1117648229a80a6
1271778b658255
132c602a534b73
141448d2a7c34d
1592ddccc3b28
hex4d2912ec461

5302425404513 has 4 divisors (see below), whose sum is σ = 5306089832640. Its totient is φ = 5298760976388.

The previous prime is 5302425404509. The next prime is 5302425404519. The reversal of 5302425404513 is 3154045242035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5302425404513 - 22 = 5302425404509 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5302425404519) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1832211893 + ... + 1832214786.

It is an arithmetic number, because the mean of its divisors is an integer number (1326522458160).

Almost surely, 25302425404513 is an apocalyptic number.

It is an amenable number.

5302425404513 is a deficient number, since it is larger than the sum of its proper divisors (3664428127).

5302425404513 is a wasteful number, since it uses less digits than its factorization.

5302425404513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3664428126.

The product of its (nonzero) digits is 288000, while the sum is 38.

The spelling of 5302425404513 in words is "five trillion, three hundred two billion, four hundred twenty-five million, four hundred four thousand, five hundred thirteen".

Divisors: 1 1447 3664426679 5302425404513