Base | Representation |
---|---|
bin | 100110100101001000100… |
… | …1011101100011010101111 |
3 | 200202220111010212111110221 |
4 | 1031022101023230122233 |
5 | 1143333331400430403 |
6 | 15135522310312211 |
7 | 1055042021201431 |
oct | 115122113543257 |
9 | 20686433774427 |
10 | 5302425405103 |
11 | 17648229a8592 |
12 | 71778b658667 |
13 | 2c602a535208 |
14 | 1448d2a7c651 |
15 | 92ddccc3dbd |
hex | 4d2912ec6af |
5302425405103 has 2 divisors, whose sum is σ = 5302425405104. Its totient is φ = 5302425405102.
The previous prime is 5302425405097. The next prime is 5302425405113. The reversal of 5302425405103 is 3015045242035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5302425405103 - 25 = 5302425405071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5302425405113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651212702551 + 2651212702552.
It is an arithmetic number, because the mean of its divisors is an integer number (2651212702552).
Almost surely, 25302425405103 is an apocalyptic number.
5302425405103 is a deficient number, since it is larger than the sum of its proper divisors (1).
5302425405103 is an equidigital number, since it uses as much as digits as its factorization.
5302425405103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 34.
The spelling of 5302425405103 in words is "five trillion, three hundred two billion, four hundred twenty-five million, four hundred five thousand, one hundred three".
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