Base | Representation |
---|---|
bin | 1111011011101010101… |
… | …11010001001100111111 |
3 | 1212200200000221111212011 |
4 | 13231311113101030333 |
5 | 32141423000331310 |
6 | 1043332105552051 |
7 | 53211042505513 |
oct | 7556527211477 |
9 | 1780600844764 |
10 | 530250011455 |
11 | 19497234286a |
12 | 869237a5627 |
13 | 3b00525a838 |
14 | 1b94294c143 |
15 | dbd669478a |
hex | 7b755d133f |
530250011455 has 8 divisors (see below), whose sum is σ = 636314688000. Its totient is φ = 424190226336.
The previous prime is 530250011407. The next prime is 530250011483. The reversal of 530250011455 is 554110052035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530250011455 - 221 = 530247914303 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 979980 + ... + 1421569.
It is an arithmetic number, because the mean of its divisors is an integer number (79539336000).
Almost surely, 2530250011455 is an apocalyptic number.
530250011455 is a deficient number, since it is larger than the sum of its proper divisors (106064676545).
530250011455 is a wasteful number, since it uses less digits than its factorization.
530250011455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2445713.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 530250011455 in words is "five hundred thirty billion, two hundred fifty million, eleven thousand, four hundred fifty-five".
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