Base | Representation |
---|---|
bin | 1111011011101010110… |
… | …11100000010110000111 |
3 | 1212200200010000221022111 |
4 | 13231311123200112013 |
5 | 32141423241401210 |
6 | 1043332145441451 |
7 | 53211055112434 |
oct | 7556533402607 |
9 | 1780603027274 |
10 | 530251122055 |
11 | 194972a31216 |
12 | 86924040287 |
13 | 3b0055591b5 |
14 | 1b942b5ab8b |
15 | dbd681388a |
hex | 7b756e0587 |
530251122055 has 8 divisors (see below), whose sum is σ = 656827196544. Its totient is φ = 410516997600.
The previous prime is 530251122047. The next prime is 530251122083. The reversal of 530251122055 is 550221152035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 530251122055 - 23 = 530251122047 is a prime.
It is a super-3 number, since 3×5302511220553 (a number of 36 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1710487336 + ... + 1710487645.
It is an arithmetic number, because the mean of its divisors is an integer number (82103399568).
Almost surely, 2530251122055 is an apocalyptic number.
530251122055 is a deficient number, since it is larger than the sum of its proper divisors (126576074489).
530251122055 is a wasteful number, since it uses less digits than its factorization.
530251122055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3420975017.
The product of its (nonzero) digits is 15000, while the sum is 31.
The spelling of 530251122055 in words is "five hundred thirty billion, two hundred fifty-one million, one hundred twenty-two thousand, fifty-five".
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