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5302540553437 is a prime number
BaseRepresentation
bin100110100101001100000…
…0010111100110011011101
3200202220210011112122022001
41031022120002330303131
51143334100340202222
615135541542322301
71055044620015031
oct115123002746335
920686704478261
105302540553437
1117648819a61a6
12717802129391
132c6048350a1a
141449040941c1
1592de7e6be27
hex4d2980bccdd

5302540553437 has 2 divisors, whose sum is σ = 5302540553438. Its totient is φ = 5302540553436.

The previous prime is 5302540553411. The next prime is 5302540553491. The reversal of 5302540553437 is 7343550452035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4943636518041 + 358904035396 = 2223429^2 + 599086^2 .

It is a cyclic number.

It is not a de Polignac number, because 5302540553437 - 231 = 5300393069789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5302540553407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2651270276718 + 2651270276719.

It is an arithmetic number, because the mean of its divisors is an integer number (2651270276719).

Almost surely, 25302540553437 is an apocalyptic number.

It is an amenable number.

5302540553437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5302540553437 is an equidigital number, since it uses as much as digits as its factorization.

5302540553437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780000, while the sum is 46.

The spelling of 5302540553437 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-three thousand, four hundred thirty-seven".