5302541314045 has 4 divisors (see below), whose sum is σ = 6363049576860. Its totient is φ = 4242033051232.

The previous prime is 5302541314043. The next prime is 5302541314051. The reversal of 5302541314045 is 5404131452035.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2192182282404 + 3110359031641 = 1480602^2 + 1763621^2 .

It is a cyclic number.

It is not a de Polignac number, because 5302541314045 - 2¹ = 5302541314043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5302541313995 and 5302541314013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5302541314043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530254131400 + ... + 530254131409.

It is an arithmetic number, because the mean of its divisors is an integer number (1590762394215).

Almost surely, 2^{5302541314045} is an apocalyptic number.

It is an amenable number.

5302541314045 is a deficient number, since it is larger than the sum of its proper divisors (1060508262815).

5302541314045 is a wasteful number, since it uses less digits than its factorization.

5302541314045 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1060508262814.

The product of its (nonzero) digits is 144000, while the sum is 37.

The spelling of 5302541314045 in words is "five trillion, three hundred two billion, five hundred forty-one million, three hundred fourteen thousand, forty-five".