Base | Representation |
---|---|
bin | 111100010010011101110101… |
… | …0001101101110100111000011 |
3 | 2120112122112010121011111110021 |
4 | 1320210323222031232213003 |
5 | 1024001443123111120301 |
6 | 5115510030032514311 |
7 | 216462111055641361 |
oct | 17044735215564703 |
9 | 2515575117144407 |
10 | 530303541504451 |
11 | 143a75518215900 |
12 | 4b5884670ab997 |
13 | 199b95425706b0 |
14 | 94d4b8502c631 |
15 | 414962ac408a1 |
hex | 1e24eea36e9c3 |
530303541504451 has 24 divisors (see below), whose sum is σ = 627760417745552. Its totient is φ = 444991062225600.
The previous prime is 530303541504439. The next prime is 530303541504481. The reversal of 530303541504451 is 154405145303035.
It is not a de Polignac number, because 530303541504451 - 211 = 530303541502403 is a prime.
It is a super-2 number, since 2×5303035415044512 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 530303541504398 and 530303541504407.
It is not an unprimeable number, because it can be changed into a prime (530303541504431) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29944600 + ... + 44241226.
Almost surely, 2530303541504451 is an apocalyptic number.
530303541504451 is a deficient number, since it is larger than the sum of its proper divisors (97456876241101).
530303541504451 is a wasteful number, since it uses less digits than its factorization.
530303541504451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14320243 (or 14320232 counting only the distinct ones).
The product of its (nonzero) digits is 1080000, while the sum is 43.
Adding to 530303541504451 its reverse (154405145303035), we get a palindrome (684708686807486).
The spelling of 530303541504451 in words is "five hundred thirty trillion, three hundred three billion, five hundred forty-one million, five hundred four thousand, four hundred fifty-one".
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