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530305132503 = 31734929794097
BaseRepresentation
bin1111011011110001010…
…01100010011111010111
31212200210212122221201110
413231320221202133113
532142031103220003
61043341355230103
753212312152336
oct7557051423727
91780725587643
10530305132503
111949a0471053
128693a148333
133b0137b9b43
141b949db9d1d
15dbdb431a03
hex7b78a627d7

530305132503 has 16 divisors (see below), whose sum is σ = 750811269600. Its totient is φ = 331787053056.

The previous prime is 530305132499. The next prime is 530305132507. The reversal of 530305132503 is 305231503035.

It is an interprime number because it is at equal distance from previous prime (530305132499) and next prime (530305132507).

It is not a de Polignac number, because 530305132503 - 22 = 530305132499 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530305132507) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14879250 + ... + 14914847.

It is an arithmetic number, because the mean of its divisors is an integer number (46925704350).

Almost surely, 2530305132503 is an apocalyptic number.

530305132503 is a deficient number, since it is larger than the sum of its proper divisors (220506137097).

530305132503 is a wasteful number, since it uses less digits than its factorization.

530305132503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29794466.

The product of its (nonzero) digits is 20250, while the sum is 30.

Adding to 530305132503 its reverse (305231503035), we get a palindrome (835536635538).

The spelling of 530305132503 in words is "five hundred thirty billion, three hundred five million, one hundred thirty-two thousand, five hundred three".

Divisors: 1 3 17 51 349 1047 5933 17799 29794097 89382291 506499649 1519498947 10398139853 31194419559 176768377501 530305132503