Base | Representation |
---|---|
bin | 110001011000110111… |
… | …010110111101111011 |
3 | 12001212210021021001200 |
4 | 301120313112331323 |
5 | 1332101302431210 |
6 | 40210055545243 |
7 | 3555100636104 |
oct | 613067267573 |
9 | 161783237050 |
10 | 53030514555 |
11 | 20543385537 |
12 | a33b98b223 |
13 | 50018794c5 |
14 | 27d0ddb3ab |
15 | 15a59650c0 |
hex | c58dd6f7b |
53030514555 has 12 divisors (see below), whose sum is σ = 91919558640. Its totient is φ = 28282941072.
The previous prime is 53030514553. The next prime is 53030514569. The reversal of 53030514555 is 55541503035.
53030514555 is a `hidden beast` number, since 53 + 0 + 3 + 0 + 51 + 4 + 555 = 666.
It is not a de Polignac number, because 53030514555 - 21 = 53030514553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53030514553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 589227895 + ... + 589227984.
It is an arithmetic number, because the mean of its divisors is an integer number (7659963220).
Almost surely, 253030514555 is an apocalyptic number.
53030514555 is a deficient number, since it is larger than the sum of its proper divisors (38889044085).
53030514555 is a wasteful number, since it uses less digits than its factorization.
53030514555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1178455890 (or 1178455887 counting only the distinct ones).
The product of its (nonzero) digits is 112500, while the sum is 36.
The spelling of 53030514555 in words is "fifty-three billion, thirty million, five hundred fourteen thousand, five hundred fifty-five".
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