5303142121 has 4 divisors (see below), whose sum is σ = 5304889044. Its totient is φ = 5301395200.

The previous prime is 5303142113. The next prime is 5303142133. The reversal of 5303142121 is 1212413035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4201632400 + 1101509721 = 64820^2 + 33189^2 .

It is a cyclic number.

It is not a de Polignac number, because 5303142121 - 2³ = 5303142113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5303142092 and 5303142101.

It is not an unprimeable number, because it can be changed into a prime (5303142161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 868900 + ... + 874981.

It is an arithmetic number, because the mean of its divisors is an integer number (1326222261).

Almost surely, 2^5303142121 is an apocalyptic number.

It is an amenable number.

5303142121 is a deficient number, since it is larger than the sum of its proper divisors (1746923).

5303142121 is a wasteful number, since it uses less digits than its factorization.

5303142121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1746922.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 5303142121 is about 72822.6758709126. The cubic root of 5303142121 is about 1743.8578822597.

Adding to 5303142121 its reverse (1212413035), we get a palindrome (6515555156).

The spelling of 5303142121 in words is "five billion, three hundred three million, one hundred forty-two thousand, one hundred twenty-one".