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5303152443055 = 51079912434473
BaseRepresentation
bin100110100101011110010…
…0001000111111010101111
3200202222100210220212001111
41031022330201013322233
51143341324011134210
615140122401252451
71055066030003545
oct115127441077257
920688323825044
105303152443055
1117650663349a5
12717953034127
132c611505029c
14144961453d95
1592e31a3788a
hex4d2bc847eaf

5303152443055 has 8 divisors (see below), whose sum is σ = 6423257539152. Its totient is φ = 4202872216128.

The previous prime is 5303152443047. The next prime is 5303152443091. The reversal of 5303152443055 is 5503442513035.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5303152443055 - 23 = 5303152443047 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5303152442999 and 5303152443017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4956216702 + ... + 4956217771.

It is an arithmetic number, because the mean of its divisors is an integer number (802907192394).

Almost surely, 25303152443055 is an apocalyptic number.

5303152443055 is a deficient number, since it is larger than the sum of its proper divisors (1120105096097).

5303152443055 is a wasteful number, since it uses less digits than its factorization.

5303152443055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9912434585.

The product of its (nonzero) digits is 540000, while the sum is 40.

The spelling of 5303152443055 in words is "five trillion, three hundred three billion, one hundred fifty-two million, four hundred forty-three thousand, fifty-five".

Divisors: 1 5 107 535 9912434473 49562172365 1060630488611 5303152443055