Base | Representation |
---|---|
bin | 111100010010100101110101… |
… | …1101011000011001100101011 |
3 | 2120112201011112121011011102020 |
4 | 1320211023223223003030223 |
5 | 1024002233341413243410 |
6 | 5115521553133235523 |
7 | 216463260313234344 |
oct | 17045135353031453 |
9 | 2515634477134366 |
10 | 530320745837355 |
11 | 143a81846656850 |
12 | 4b58b868932ba3 |
13 | 199bb0549a7335 |
14 | 94d5937cdb0cb |
15 | 4149cd632aa70 |
hex | 1e252ebac332b |
530320745837355 has 64 divisors (see below), whose sum is σ = 925973619056640. Its totient is φ = 257035542192000.
The previous prime is 530320745837347. The next prime is 530320745837383. The reversal of 530320745837355 is 553738547023035.
It is not a de Polignac number, because 530320745837355 - 23 = 530320745837347 is a prime.
It is a super-2 number, since 2×5303207458373552 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5969145564 + ... + 5969234406.
It is an arithmetic number, because the mean of its divisors is an integer number (14468337797760).
Almost surely, 2530320745837355 is an apocalyptic number.
530320745837355 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
530320745837355 is a deficient number, since it is larger than the sum of its proper divisors (395652873219285).
530320745837355 is a wasteful number, since it uses less digits than its factorization.
530320745837355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101072.
The product of its (nonzero) digits is 158760000, while the sum is 60.
The spelling of 530320745837355 in words is "five hundred thirty trillion, three hundred twenty billion, seven hundred forty-five million, eight hundred thirty-seven thousand, three hundred fifty-five".
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