Base | Representation |
---|---|
bin | 110001011000111110… |
… | …001101110100100111 |
3 | 12001212220122120211112 |
4 | 301120332031310213 |
5 | 1332102232441403 |
6 | 40210202255235 |
7 | 3555122133551 |
oct | 613076156447 |
9 | 161786576745 |
10 | 53032312103 |
11 | 205443a3011 |
12 | a3404b751b |
13 | 5002058744 |
14 | 27d13484d1 |
15 | 15a5bbc9d8 |
hex | c58f8dd27 |
53032312103 has 2 divisors, whose sum is σ = 53032312104. Its totient is φ = 53032312102.
The previous prime is 53032312087. The next prime is 53032312111. The reversal of 53032312103 is 30121323035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53032312103 - 24 = 53032312087 is a prime.
It is a super-2 number, since 2×530323121032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53032312163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26516156051 + 26516156052.
It is an arithmetic number, because the mean of its divisors is an integer number (26516156052).
Almost surely, 253032312103 is an apocalyptic number.
53032312103 is a deficient number, since it is larger than the sum of its proper divisors (1).
53032312103 is an equidigital number, since it uses as much as digits as its factorization.
53032312103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 23.
Adding to 53032312103 its reverse (30121323035), we get a palindrome (83153635138).
The spelling of 53032312103 in words is "fifty-three billion, thirty-two million, three hundred twelve thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •