Base | Representation |
---|---|
bin | 110001011000111110… |
… | …001101110100111111 |
3 | 12001212220122120212102 |
4 | 301120332031310333 |
5 | 1332102232442002 |
6 | 40210202255315 |
7 | 3555122133614 |
oct | 613076156477 |
9 | 161786576772 |
10 | 53032312127 |
11 | 205443a3033 |
12 | a3404b753b |
13 | 5002058762 |
14 | 27d134850b |
15 | 15a5bbca02 |
hex | c58f8dd3f |
53032312127 has 2 divisors, whose sum is σ = 53032312128. Its totient is φ = 53032312126.
The previous prime is 53032312111. The next prime is 53032312129. The reversal of 53032312127 is 72121323035.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53032312127 - 24 = 53032312111 is a prime.
It is a super-2 number, since 2×530323121272 (a number of 22 digits) contains 22 as substring.
Together with 53032312129, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 53032312127.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53032312129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26516156063 + 26516156064.
It is an arithmetic number, because the mean of its divisors is an integer number (26516156064).
Almost surely, 253032312127 is an apocalyptic number.
53032312127 is a deficient number, since it is larger than the sum of its proper divisors (1).
53032312127 is an equidigital number, since it uses as much as digits as its factorization.
53032312127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 29.
The spelling of 53032312127 in words is "fifty-three billion, thirty-two million, three hundred twelve thousand, one hundred twenty-seven".
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