Base | Representation |
---|---|
bin | 11000000111011110011011… |
… | …01001011110000111000111 |
3 | 20221202221111121212201210221 |
4 | 30003233031221132013013 |
5 | 23422344411304413411 |
6 | 304443113551125211 |
7 | 14112352242060046 |
oct | 1403571551360707 |
9 | 227687447781727 |
10 | 53033411404231 |
11 | 15997386183335 |
12 | 5b46292213807 |
13 | 237904c30484b |
14 | d14b8ba4455d |
15 | 61e7c2739071 |
hex | 303bcda5e1c7 |
53033411404231 has 8 divisors (see below), whose sum is σ = 56153132867520. Its totient is φ = 49913702055168.
The previous prime is 53033411404201. The next prime is 53033411404241. The reversal of 53033411404231 is 13240411433035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53033411404231 - 237 = 52895972450759 is a prime.
It is a super-2 number, since 2×530334114042312 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53033411404201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6917875 + ... + 12406603.
It is an arithmetic number, because the mean of its divisors is an integer number (7019141608440).
Almost surely, 253033411404231 is an apocalyptic number.
53033411404231 is a deficient number, since it is larger than the sum of its proper divisors (3119721463289).
53033411404231 is a wasteful number, since it uses less digits than its factorization.
53033411404231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6057113.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 53033411404231 its reverse (13240411433035), we get a palindrome (66273822837266).
The spelling of 53033411404231 in words is "fifty-three trillion, thirty-three billion, four hundred eleven million, four hundred four thousand, two hundred thirty-one".
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