Base | Representation |
---|---|
bin | 111100010010101100101111… |
… | …0010000101010011110000111 |
3 | 2120112202120202112211020011001 |
4 | 1320211121132100222132013 |
5 | 1024003004203104431210 |
6 | 5115532442330354131 |
7 | 216464323253611666 |
oct | 17045313620523607 |
9 | 2515676675736131 |
10 | 530335553202055 |
11 | 143a88054a66037 |
12 | 4b5926bb88b947 |
13 | 199bc5746472b3 |
14 | 94d65406d8ddd |
15 | 414a3a128d03a |
hex | 1e2565e42a787 |
530335553202055 has 8 divisors (see below), whose sum is σ = 636969362570352. Its totient is φ = 423890643409728.
The previous prime is 530335553202043. The next prime is 530335553202163. The reversal of 530335553202055 is 550202355533035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530335553202055 - 239 = 529785797388167 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 530335553201996 and 530335553202014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47224887814 + ... + 47224899043.
It is an arithmetic number, because the mean of its divisors is an integer number (79621170321294).
Almost surely, 2530335553202055 is an apocalyptic number.
530335553202055 is a deficient number, since it is larger than the sum of its proper divisors (106633809368297).
530335553202055 is a wasteful number, since it uses less digits than its factorization.
530335553202055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 94449787985.
The product of its (nonzero) digits is 5062500, while the sum is 46.
The spelling of 530335553202055 in words is "five hundred thirty trillion, three hundred thirty-five billion, five hundred fifty-three million, two hundred two thousand, fifty-five".
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