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530340043153909 is a prime number
BaseRepresentation
bin111100010010101110110100…
…1111000011110000111110101
32120112210000100110110102012011
41320211131221320132013311
51024003042402021411114
65115534504041524221
7216464542443562432
oct17045355170360765
92515700313412164
10530340043153909
11143a89a4947334a
124b5935534a3671
13199bcb0b913341
1494d6848b4ab89
15414a5655441c4
hex1e25769e1e1f5

530340043153909 has 2 divisors, whose sum is σ = 530340043153910. Its totient is φ = 530340043153908.

The previous prime is 530340043153903. The next prime is 530340043154017. The reversal of 530340043153909 is 909351340043035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 426302531939025 + 104037511214884 = 20647095^2 + 10199878^2 .

It is a cyclic number.

It is not a de Polignac number, because 530340043153909 - 29 = 530340043153397 is a prime.

It is a super-2 number, since 2×5303400431539092 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (530340043153903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265170021576954 + 265170021576955.

It is an arithmetic number, because the mean of its divisors is an integer number (265170021576955).

Almost surely, 2530340043153909 is an apocalyptic number.

It is an amenable number.

530340043153909 is a deficient number, since it is larger than the sum of its proper divisors (1).

530340043153909 is an equidigital number, since it uses as much as digits as its factorization.

530340043153909 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2624400, while the sum is 49.

The spelling of 530340043153909 in words is "five hundred thirty trillion, three hundred forty billion, forty-three million, one hundred fifty-three thousand, nine hundred nine".