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530340043154017 is a prime number
BaseRepresentation
bin111100010010101110110100…
…1111000011110001001100001
32120112210000100110110102100011
41320211131221320132021201
51024003042402021412032
65115534504041524521
7216464542443562645
oct17045355170361141
92515700313412304
10530340043154017
11143a89a49473438
124b5935534a3741
13199bcb0b9133c5
1494d6848b4ac25
15414a565544247
hex1e25769e1e261

530340043154017 has 2 divisors, whose sum is σ = 530340043154018. Its totient is φ = 530340043154016.

The previous prime is 530340043153909. The next prime is 530340043154023. The reversal of 530340043154017 is 710451340043035.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 474448510221921 + 55891532932096 = 21781839^2 + 7476064^2 .

It is a cyclic number.

It is not a de Polignac number, because 530340043154017 - 211 = 530340043151969 is a prime.

It is a super-2 number, since 2×5303400431540172 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (530340043154057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265170021577008 + 265170021577009.

It is an arithmetic number, because the mean of its divisors is an integer number (265170021577009).

Almost surely, 2530340043154017 is an apocalyptic number.

It is an amenable number.

530340043154017 is a deficient number, since it is larger than the sum of its proper divisors (1).

530340043154017 is an equidigital number, since it uses as much as digits as its factorization.

530340043154017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 40.

The spelling of 530340043154017 in words is "five hundred thirty trillion, three hundred forty billion, forty-three million, one hundred fifty-four thousand, seventeen".