Base | Representation |
---|---|
bin | 11000000111100000101011… |
… | …10011100101011100010110 |
3 | 20221210001121222212010221020 |
4 | 30003300111303211130112 |
5 | 23422404401213442004 |
6 | 304443434034502010 |
7 | 14112424242101205 |
oct | 1403602563453426 |
9 | 227701558763836 |
10 | 53034622015254 |
11 | 15997947577310 |
12 | 5b4656b734906 |
13 | 23791b3072a29 |
14 | d14c6473723c |
15 | 61e843b6d8d9 |
hex | 303c15ce5716 |
53034622015254 has 32 divisors (see below), whose sum is σ = 120742854868224. Its totient is φ = 15372354206880.
The previous prime is 53034622015237. The next prime is 53034622015259. The reversal of 53034622015254 is 45251022643035.
It is a super-3 number, since 3×530346220152543 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53034622015259) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17468582809 + ... + 17468585844.
It is an arithmetic number, because the mean of its divisors is an integer number (3773214214632).
Almost surely, 253034622015254 is an apocalyptic number.
53034622015254 is an abundant number, since it is smaller than the sum of its proper divisors (67708232852970).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53034622015254 is a wasteful number, since it uses less digits than its factorization.
53034622015254 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34937168692.
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 53034622015254 its reverse (45251022643035), we get a palindrome (98285644658289).
The spelling of 53034622015254 in words is "fifty-three trillion, thirty-four billion, six hundred twenty-two million, fifteen thousand, two hundred fifty-four".
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