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530350430351335 = 51175831271625359
BaseRepresentation
bin111100010010110011101010…
…1000000011110111111100111
32120112211000011100210201022221
41320211213111000132333213
51024003230140132220320
65115543342455333211
7216465361032365026
oct17045472500367747
92515730140721287
10530350430351335
11143a933997a9530
124b595572081207
13199c0aa58ab9c9
1494d71524a08bd
15414a9723d73aa
hex1e259d501efe7

530350430351335 has 16 divisors (see below), whose sum is σ = 694368484577280. Its totient is φ = 385658538574240.

The previous prime is 530350430351327. The next prime is 530350430351407. The reversal of 530350430351335 is 533153034053035.

It is not a de Polignac number, because 530350430351335 - 23 = 530350430351327 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530350430351291 and 530350430351300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 635395615 + ... + 636229744.

It is an arithmetic number, because the mean of its divisors is an integer number (43398030286080).

Almost surely, 2530350430351335 is an apocalyptic number.

530350430351335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.

530350430351335 is a deficient number, since it is larger than the sum of its proper divisors (164018054225945).

530350430351335 is a wasteful number, since it uses less digits than its factorization.

530350430351335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1271632958.

The product of its (nonzero) digits is 1822500, while the sum is 43.

The spelling of 530350430351335 in words is "five hundred thirty trillion, three hundred fifty billion, four hundred thirty million, three hundred fifty-one thousand, three hundred thirty-five".

Divisors: 1 5 11 55 7583 37915 83413 417065 1271625359 6358126795 13987878949 69939394745 9642735097297 48213675486485 106070086070267 530350430351335