Base | Representation |
---|---|
bin | 111100010010110011101010… |
… | …1000000011110111111100111 |
3 | 2120112211000011100210201022221 |
4 | 1320211213111000132333213 |
5 | 1024003230140132220320 |
6 | 5115543342455333211 |
7 | 216465361032365026 |
oct | 17045472500367747 |
9 | 2515730140721287 |
10 | 530350430351335 |
11 | 143a933997a9530 |
12 | 4b595572081207 |
13 | 199c0aa58ab9c9 |
14 | 94d71524a08bd |
15 | 414a9723d73aa |
hex | 1e259d501efe7 |
530350430351335 has 16 divisors (see below), whose sum is σ = 694368484577280. Its totient is φ = 385658538574240.
The previous prime is 530350430351327. The next prime is 530350430351407. The reversal of 530350430351335 is 533153034053035.
It is not a de Polignac number, because 530350430351335 - 23 = 530350430351327 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530350430351291 and 530350430351300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 635395615 + ... + 636229744.
It is an arithmetic number, because the mean of its divisors is an integer number (43398030286080).
Almost surely, 2530350430351335 is an apocalyptic number.
530350430351335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
530350430351335 is a deficient number, since it is larger than the sum of its proper divisors (164018054225945).
530350430351335 is a wasteful number, since it uses less digits than its factorization.
530350430351335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1271632958.
The product of its (nonzero) digits is 1822500, while the sum is 43.
The spelling of 530350430351335 in words is "five hundred thirty trillion, three hundred fifty billion, four hundred thirty million, three hundred fifty-one thousand, three hundred thirty-five".
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