Base | Representation |
---|---|
bin | 100110100101101000111… |
… | …0101010000110101100001 |
3 | 200210000021201210212022222 |
4 | 1031023101311100311201 |
5 | 1143343042032402001 |
6 | 15140222054040425 |
7 | 1055110631366111 |
oct | 115132165206541 |
9 | 20700251725288 |
10 | 5303510044001 |
11 | 176522a180874 |
12 | 717a32949115 |
13 | 2c6171168090 |
14 | 144996b3d041 |
15 | 92e5312361b |
hex | 4d2d1d50d61 |
5303510044001 has 8 divisors (see below), whose sum is σ = 6012076163520. Its totient is φ = 4637887325712.
The previous prime is 5303510043977. The next prime is 5303510044067. The reversal of 5303510044001 is 1004400153035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5303510044001 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5303510044601) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10735850045 + ... + 10735850538.
It is an arithmetic number, because the mean of its divisors is an integer number (751509520440).
Almost surely, 25303510044001 is an apocalyptic number.
It is an amenable number.
5303510044001 is a deficient number, since it is larger than the sum of its proper divisors (708566119519).
5303510044001 is a wasteful number, since it uses less digits than its factorization.
5303510044001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21471700615.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 5303510044001 its reverse (1004400153035), we get a palindrome (6307910197036).
The spelling of 5303510044001 in words is "five trillion, three hundred three billion, five hundred ten million, forty-four thousand, one".
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