Base | Representation |
---|---|
bin | 110001011001001010… |
… | …000000000001101100 |
3 | 12001220010110112110010 |
4 | 301121022000001230 |
5 | 1332104030320244 |
6 | 40210352413220 |
7 | 3555160321203 |
oct | 613112000154 |
9 | 161803415403 |
10 | 53035401324 |
11 | 20546112a94 |
12 | a341547210 |
13 | 500289a899 |
14 | 27d191023a |
15 | 15a60cceb9 |
hex | c5928006c |
53035401324 has 12 divisors (see below), whose sum is σ = 123749269784. Its totient is φ = 17678467104.
The previous prime is 53035401319. The next prime is 53035401329. The reversal of 53035401324 is 42310453035.
It is an interprime number because it is at equal distance from previous prime (53035401319) and next prime (53035401329).
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 53035401291 and 53035401300.
It is not an unprimeable number, because it can be changed into a prime (53035401329) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2209808377 + ... + 2209808400.
Almost surely, 253035401324 is an apocalyptic number.
It is an amenable number.
53035401324 is an abundant number, since it is smaller than the sum of its proper divisors (70713868460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53035401324 is a wasteful number, since it uses less digits than its factorization.
53035401324 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4419616784 (or 4419616782 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 30.
Adding to 53035401324 its reverse (42310453035), we get a palindrome (95345854359).
The spelling of 53035401324 in words is "fifty-three billion, thirty-five million, four hundred one thousand, three hundred twenty-four".
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