Base | Representation |
---|---|
bin | 100110100101101001110… |
… | …1100010010001001011000 |
3 | 200210000100220112000101011 |
4 | 1031023103230102021120 |
5 | 1143343123024311004 |
6 | 15140225130503304 |
7 | 1055111460524506 |
oct | 115132354221130 |
9 | 20700326460334 |
10 | 5303541244504 |
11 | 1765245851208 |
12 | 717a41294b34 |
13 | 2c6177770609 |
14 | 14499ad41676 |
15 | 92e55c38004 |
hex | 4d2d3b12258 |
5303541244504 has 16 divisors (see below), whose sum is σ = 9944310502800. Its totient is φ = 2651725110432.
The previous prime is 5303541244493. The next prime is 5303541244513. The reversal of 5303541244504 is 4054421453035.
It is a super-3 number, since 3×53035412445043 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5191159 + ... + 6128230.
It is an arithmetic number, because the mean of its divisors is an integer number (621519406425).
Almost surely, 25303541244504 is an apocalyptic number.
It is an amenable number.
5303541244504 is a deficient number, since it is larger than the sum of its proper divisors (4640769258296).
5303541244504 is a wasteful number, since it uses less digits than its factorization.
5303541244504 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11377962 (or 11377958 counting only the distinct ones).
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 5303541244504 its reverse (4054421453035), we get a palindrome (9357962697539).
The spelling of 5303541244504 in words is "five trillion, three hundred three billion, five hundred forty-one million, two hundred forty-four thousand, five hundred four".
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