Base | Representation |
---|---|
bin | 1111011011110111010… |
… | …01110111101101000101 |
3 | 1212200221101112110221212 |
4 | 13231323221313231011 |
5 | 32142132010113140 |
6 | 1043350400021205 |
7 | 53213463542225 |
oct | 7557351675505 |
9 | 1780841473855 |
10 | 530355551045 |
11 | 194a16978271 |
12 | 86953001805 |
13 | 3b0210908b8 |
14 | 1b952982085 |
15 | dbe0a90765 |
hex | 7b7ba77b45 |
530355551045 has 64 divisors (see below), whose sum is σ = 695826028800. Its totient is φ = 386718935040.
The previous prime is 530355551041. The next prime is 530355551051. The reversal of 530355551045 is 540155553035.
It is not a de Polignac number, because 530355551045 - 22 = 530355551041 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (41).
It is a junction number, because it is equal to n+sod(n) for n = 530355550993 and 530355551011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530355551041) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 95436407 + ... + 95441963.
It is an arithmetic number, because the mean of its divisors is an integer number (10872281700).
Almost surely, 2530355551045 is an apocalyptic number.
It is an amenable number.
530355551045 is a deficient number, since it is larger than the sum of its proper divisors (165470477755).
530355551045 is a wasteful number, since it uses less digits than its factorization.
530355551045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5958.
The product of its (nonzero) digits is 562500, while the sum is 41.
The spelling of 530355551045 in words is "five hundred thirty billion, three hundred fifty-five million, five hundred fifty-one thousand, forty-five".
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