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53040568111 = 232306111657
BaseRepresentation
bin110001011001011101…
…101101011100101111
312001220111012000221121
4301121131231130233
51332111341134421
640211055241411
73555252250546
oct613135553457
9161814160847
1053040568111
1120549021963
12a343219267
13500398955b
1427d249715d
1515a679dd41
hexc5976d72f

53040568111 has 4 divisors (see below), whose sum is σ = 55346679792. Its totient is φ = 50734456432.

The previous prime is 53040568081. The next prime is 53040568181. The reversal of 53040568111 is 11186504035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53040568111 - 215 = 53040535343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53040568181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1153055806 + ... + 1153055851.

It is an arithmetic number, because the mean of its divisors is an integer number (13836669948).

Almost surely, 253040568111 is an apocalyptic number.

53040568111 is a deficient number, since it is larger than the sum of its proper divisors (2306111681).

53040568111 is a wasteful number, since it uses less digits than its factorization.

53040568111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2306111680.

The product of its (nonzero) digits is 14400, while the sum is 34.

The spelling of 53040568111 in words is "fifty-three billion, forty million, five hundred sixty-eight thousand, one hundred eleven".

Divisors: 1 23 2306111657 53040568111