Base | Representation |
---|---|
bin | 111100010011010100100010… |
… | …1000110000101101100111100 |
3 | 2120120001202101121011000111211 |
4 | 1320212221011012011230330 |
5 | 1024010404232232024112 |
6 | 5120040020222254204 |
7 | 216503440413420634 |
oct | 17046510506055474 |
9 | 2516052347130454 |
10 | 530421030345532 |
11 | 144010328645077 |
12 | 4b5a7195a27364 |
13 | 199c764741c3c1 |
14 | 94da72ca5b6c4 |
15 | 414c7055140a7 |
hex | 1e26a45185b3c |
530421030345532 has 12 divisors (see below), whose sum is σ = 929156760300160. Its totient is φ = 264947670259776.
The previous prime is 530421030345523. The next prime is 530421030345539. The reversal of 530421030345532 is 235543030124035.
It is a super-3 number, since 3×5304210303455323 (a number of 45 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530421030345539) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65711223708 + ... + 65711231779.
Almost surely, 2530421030345532 is an apocalyptic number.
It is an amenable number.
530421030345532 is a deficient number, since it is larger than the sum of its proper divisors (398735729954628).
530421030345532 is a wasteful number, since it uses less digits than its factorization.
530421030345532 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131422456500 (or 131422456498 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 40.
Adding to 530421030345532 its reverse (235543030124035), we get a palindrome (765964060469567).
The spelling of 530421030345532 in words is "five hundred thirty trillion, four hundred twenty-one billion, thirty million, three hundred forty-five thousand, five hundred thirty-two".
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