53043411511 has 4 divisors (see below), whose sum is σ = 53095982800. Its totient is φ = 52990840224.

The previous prime is 53043411493. The next prime is 53043411563. The reversal of 53043411511 is 11511434035.

53043411511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11511434035 = 5 ⋅2302286807.

It is a cyclic number.

It is not a de Polignac number, because 53043411511 - 2⁷ = 53043411383 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53043411511.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53043411581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26284131 + ... + 26286148.

It is an arithmetic number, because the mean of its divisors is an integer number (13273995700).

Almost surely, 2^53043411511 is an apocalyptic number.

53043411511 is a deficient number, since it is larger than the sum of its proper divisors (52571289).

53043411511 is a wasteful number, since it uses less digits than its factorization.

53043411511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52571288.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 53043411511 its reverse (11511434035), we get a palindrome (64554845546).

The spelling of 53043411511 in words is "fifty-three billion, forty-three million, four hundred eleven thousand, five hundred eleven".