Base | Representation |
---|---|
bin | 110001011001101011… |
… | …100100001011000101 |
3 | 12001220202000120010221 |
4 | 301121223210023011 |
5 | 1332113303401013 |
6 | 40211305144341 |
7 | 3555325155541 |
oct | 613153441305 |
9 | 161822016127 |
10 | 53044200133 |
11 | 20550082731 |
12 | a34448b0b1 |
13 | 500465b792 |
14 | 27d2b60a21 |
15 | 15a6c6a08d |
hex | c59ae42c5 |
53044200133 has 16 divisors (see below), whose sum is σ = 58365964800. Its totient is φ = 47983106160.
The previous prime is 53044200127. The next prime is 53044200151. The reversal of 53044200133 is 33100244035.
It is a de Polignac number, because none of the positive numbers 2k-53044200133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53044200098 and 53044200107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53044203133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 143238 + ... + 355816.
It is an arithmetic number, because the mean of its divisors is an integer number (3647872800).
Almost surely, 253044200133 is an apocalyptic number.
It is an amenable number.
53044200133 is a deficient number, since it is larger than the sum of its proper divisors (5321764667).
53044200133 is a wasteful number, since it uses less digits than its factorization.
53044200133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 213192.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 53044200133 its reverse (33100244035), we get a palindrome (86144444168).
The spelling of 53044200133 in words is "fifty-three billion, forty-four million, two hundred thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •