Base | Representation |
---|---|
bin | 110001011001101011… |
… | …101010000000000000 |
3 | 12001220202001202212220 |
4 | 301121223222000000 |
5 | 1332113310132000 |
6 | 40211305451040 |
7 | 3555325315245 |
oct | 613153520000 |
9 | 161822052786 |
10 | 53044224000 |
11 | 20550099659 |
12 | a3444a0a80 |
13 | 50046695c1 |
14 | 27d2b695cc |
15 | 15a6c721a0 |
hex | c59aea000 |
53044224000 has 448 divisors, whose sum is σ = 182541745152. Its totient is φ = 13664256000.
The previous prime is 53044223957. The next prime is 53044224011. The reversal of 53044224000 is 42244035.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 95231722 + ... + 95232278.
Almost surely, 253044224000 is an apocalyptic number.
53044224000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53044224000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (91270872576).
53044224000 is an abundant number, since it is smaller than the sum of its proper divisors (129497521152).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53044224000 is an equidigital number, since it uses as much as digits as its factorization.
53044224000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 632 (or 598 counting only the distinct ones).
The product of its (nonzero) digits is 3840, while the sum is 24.
Adding to 53044224000 its reverse (42244035), we get a palindrome (53086468035).
The spelling of 53044224000 in words is "fifty-three billion, forty-four million, two hundred twenty-four thousand".
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