Base | Representation |
---|---|
bin | 100110100110000110101… |
… | …1011111101001110101011 |
3 | 200210002212102111002010211 |
4 | 1031030031123331032223 |
5 | 1143402114032334201 |
6 | 15140505215321551 |
7 | 1055144463264202 |
oct | 115141533751653 |
9 | 20702772432124 |
10 | 5304510043051 |
11 | 17656a26a396a |
12 | 7180718202b7 |
13 | 2c62a03a49ab |
14 | 144a4d88a239 |
15 | 92eb0d04651 |
hex | 4d30d6fd3ab |
5304510043051 has 8 divisors (see below), whose sum is σ = 5536266289920. Its totient is φ = 5072847577512.
The previous prime is 5304510042943. The next prime is 5304510043069. The reversal of 5304510043051 is 1503400154035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5304510043051 - 217 = 5304509911979 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5304510047051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23329725 + ... + 23555998.
It is an arithmetic number, because the mean of its divisors is an integer number (692033286240).
Almost surely, 25304510043051 is an apocalyptic number.
5304510043051 is a deficient number, since it is larger than the sum of its proper divisors (231756246869).
5304510043051 is a wasteful number, since it uses less digits than its factorization.
5304510043051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46890665.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 5304510043051 its reverse (1503400154035), we get a palindrome (6807910197086).
The spelling of 5304510043051 in words is "five trillion, three hundred four billion, five hundred ten million, forty-three thousand, fifty-one".
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