Base | Representation |
---|---|
bin | 100110100110000110101… |
… | …1011111101001110101010 |
3 | 200210002212102111002010210 |
4 | 1031030031123331032222 |
5 | 1143402114032334200 |
6 | 15140505215321550 |
7 | 1055144463264201 |
oct | 115141533751652 |
9 | 20702772432123 |
10 | 5304510043050 |
11 | 17656a26a3969 |
12 | 7180718202b6 |
13 | 2c62a03a49aa |
14 | 144a4d88a238 |
15 | 92eb0d04650 |
hex | 4d30d6fd3aa |
5304510043050 has 48 divisors (see below), whose sum is σ = 13158579484512. Its totient is φ = 1414171003200.
The previous prime is 5304510042943. The next prime is 5304510043069. The reversal of 5304510043050 is 503400154035.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 5304510042999 and 5304510043017.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3979116 + ... + 5142215.
It is an arithmetic number, because the mean of its divisors is an integer number (274137072594).
Almost surely, 25304510043050 is an apocalyptic number.
5304510043050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5304510043050 is an abundant number, since it is smaller than the sum of its proper divisors (7854069441462).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5304510043050 is a wasteful number, since it uses less digits than its factorization.
5304510043050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9125223 (or 9125218 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 30.
Adding to 5304510043050 its reverse (503400154035), we get a palindrome (5807910197085).
The spelling of 5304510043050 in words is "five trillion, three hundred four billion, five hundred ten million, forty-three thousand, fifty".
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