53050401300053 has 2 divisors, whose sum is σ = 53050401300054. Its totient is φ = 53050401300052.

The previous prime is 53050401300049. The next prime is 53050401300109. The reversal of 53050401300053 is 35000310405035.

53050401300053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39727594698289 + 13322806601764 = 6302983^2 + 3650042^2 .

It is a cyclic number.

It is not a de Polignac number, because 53050401300053 - 2² = 53050401300049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53050401299989 and 53050401300025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53050401305053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26525200650026 + 26525200650027.

It is an arithmetic number, because the mean of its divisors is an integer number (26525200650027).

Almost surely, 2^{53050401300053} is an apocalyptic number.

It is an amenable number.

53050401300053 is a deficient number, since it is larger than the sum of its proper divisors (1).

53050401300053 is an equidigital number, since it uses as much as digits as its factorization.

53050401300053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13500, while the sum is 29.

Adding to 53050401300053 its reverse (35000310405035), we get a palindrome (88050711705088).

The spelling of 53050401300053 in words is "fifty-three trillion, fifty billion, four hundred one million, three hundred thousand, fifty-three".