Base | Representation |
---|---|
bin | 110001011010001001… |
… | …110000011001111011 |
3 | 12001221021220122200200 |
4 | 301122021300121323 |
5 | 1332122320131210 |
6 | 40212150533243 |
7 | 3555452350626 |
oct | 613211603173 |
9 | 161837818620 |
10 | 53052114555 |
11 | 20554598980 |
12 | a347067223 |
13 | 500619cc7b |
14 | 27d3c20dbd |
15 | 15a77d00c0 |
hex | c5a27067b |
53052114555 has 48 divisors (see below), whose sum is σ = 100365838560. Its totient is φ = 25709644800.
The previous prime is 53052114539. The next prime is 53052114559. The reversal of 53052114555 is 55541125035.
53052114555 is a `hidden beast` number, since 53 + 0 + 52 + 1 + 1 + 4 + 555 = 666.
53052114555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53052114555 - 24 = 53052114539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53052114559) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1028685 + ... + 1079025.
It is an arithmetic number, because the mean of its divisors is an integer number (2090954970).
Almost surely, 253052114555 is an apocalyptic number.
53052114555 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53052114555 is a deficient number, since it is larger than the sum of its proper divisors (47313724005).
53052114555 is a wasteful number, since it uses less digits than its factorization.
53052114555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52492 (or 52489 counting only the distinct ones).
The product of its (nonzero) digits is 75000, while the sum is 36.
The spelling of 53052114555 in words is "fifty-three billion, fifty-two million, one hundred fourteen thousand, five hundred fifty-five".
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