Base | Representation |
---|---|
bin | 11000001000000001101101… |
… | …01001111110001010011111 |
3 | 20221211202101200212010101121 |
4 | 30010000312221332022133 |
5 | 23423202204332344013 |
6 | 304455525311351411 |
7 | 14113622523064324 |
oct | 1404006651761237 |
9 | 227752350763347 |
10 | 53052353012383 |
11 | 159a441622694a |
12 | 5b49a99822567 |
13 | 237aa7a6392ca |
14 | d15a6753cb4b |
15 | 6200305dc58d |
hex | 304036a7e29f |
53052353012383 has 2 divisors, whose sum is σ = 53052353012384. Its totient is φ = 53052353012382.
The previous prime is 53052353012363. The next prime is 53052353012471. The reversal of 53052353012383 is 38321035325035.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53052353012383 - 213 = 53052353004191 is a prime.
It is a super-3 number, since 3×530523530123833 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53052353012333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26526176506191 + 26526176506192.
It is an arithmetic number, because the mean of its divisors is an integer number (26526176506192).
Almost surely, 253052353012383 is an apocalyptic number.
53052353012383 is a deficient number, since it is larger than the sum of its proper divisors (1).
53052353012383 is an equidigital number, since it uses as much as digits as its factorization.
53052353012383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972000, while the sum is 43.
The spelling of 53052353012383 in words is "fifty-three trillion, fifty-two billion, three hundred fifty-three million, twelve thousand, three hundred eighty-three".
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