Base | Representation |
---|---|
bin | 100110100110011110100… |
… | …1011111000010100111011 |
3 | 200210011221020212202202022 |
4 | 1031030331023320110323 |
5 | 1143410234122310120 |
6 | 15141120513425055 |
7 | 1055203361406302 |
oct | 115147513702473 |
9 | 20704836782668 |
10 | 5305311135035 |
11 | 1765a7391015a |
12 | 718255b6b18b |
13 | 2c639a34a912 |
14 | 144ac801b439 |
15 | 9300b2e5025 |
hex | 4d33d2f853b |
5305311135035 has 16 divisors (see below), whose sum is σ = 6487466955840. Its totient is φ = 4163543879040.
The previous prime is 5305311134987. The next prime is 5305311135037.
It is a happy number.
5305311135035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5305311135035 - 214 = 5305311118651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5305311134986 and 5305311135004.
It is not an unprimeable number, because it can be changed into a prime (5305311135037) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 271205 + ... + 3268665.
It is an arithmetic number, because the mean of its divisors is an integer number (405466684740).
Almost surely, 25305311135035 is an apocalyptic number.
5305311135035 is a deficient number, since it is larger than the sum of its proper divisors (1182155820805).
5305311135035 is a wasteful number, since it uses less digits than its factorization.
5305311135035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3004198.
The product of its (nonzero) digits is 50625, while the sum is 35.
The spelling of 5305311135035 in words is "five trillion, three hundred five billion, three hundred eleven million, one hundred thirty-five thousand, thirty-five".
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