Base | Representation |
---|---|
bin | 110001011010010000… |
… | …111101101111111111 |
3 | 12001221102110122211101 |
4 | 301122100331233333 |
5 | 1332123311113343 |
6 | 40212255233531 |
7 | 3555504411103 |
oct | 613220755777 |
9 | 161842418741 |
10 | 53054004223 |
11 | 20555669690 |
12 | a3478188a7 |
13 | 50066b210c |
14 | 27d4193903 |
15 | 15a7a54e4d |
hex | c5a43dbff |
53054004223 has 16 divisors (see below), whose sum is σ = 59954942880. Its totient is φ = 46525811200.
The previous prime is 53054004217. The next prime is 53054004253. The reversal of 53054004223 is 32240045035.
It is not a de Polignac number, because 53054004223 - 229 = 52517133311 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 53054004191 and 53054004200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53054004253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 620740 + ... + 701017.
It is an arithmetic number, because the mean of its divisors is an integer number (3747183930).
Almost surely, 253054004223 is an apocalyptic number.
53054004223 is a deficient number, since it is larger than the sum of its proper divisors (6900938657).
53054004223 is a wasteful number, since it uses less digits than its factorization.
53054004223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1321898.
The product of its (nonzero) digits is 14400, while the sum is 28.
Adding to 53054004223 its reverse (32240045035), we get a palindrome (85294049258).
The spelling of 53054004223 in words is "fifty-three billion, fifty-four million, four thousand, two hundred twenty-three".
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