Base | Representation |
---|---|
bin | 1111011100001101011… |
… | …11011001101000011111 |
3 | 1212201102100112012201011 |
4 | 13232012233121220133 |
5 | 32143022114100421 |
6 | 1043421042400051 |
7 | 53221212524446 |
oct | 7560657315037 |
9 | 1781370465634 |
10 | 530541550111 |
11 | 195001968101 |
12 | 869a5360027 |
13 | 3b050785211 |
14 | 1b96d55bd5d |
15 | dc020814e1 |
hex | 7b86bd9a1f |
530541550111 has 4 divisors (see below), whose sum is σ = 530546291424. Its totient is φ = 530536808800.
The previous prime is 530541550073. The next prime is 530541550171. The reversal of 530541550111 is 111055145035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-530541550111 is a prime.
It is a super-2 number, since 2×5305415501112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530541550171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198650 + ... + 2427991.
It is an arithmetic number, because the mean of its divisors is an integer number (132636572856).
Almost surely, 2530541550111 is an apocalyptic number.
530541550111 is a deficient number, since it is larger than the sum of its proper divisors (4741313).
530541550111 is a wasteful number, since it uses less digits than its factorization.
530541550111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4741312.
The product of its (nonzero) digits is 7500, while the sum is 31.
Adding to 530541550111 its reverse (111055145035), we get a palindrome (641596695146).
The spelling of 530541550111 in words is "five hundred thirty billion, five hundred forty-one million, five hundred fifty thousand, one hundred eleven".
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