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530541550111 = 1146714626641
BaseRepresentation
bin1111011100001101011…
…11011001101000011111
31212201102100112012201011
413232012233121220133
532143022114100421
61043421042400051
753221212524446
oct7560657315037
91781370465634
10530541550111
11195001968101
12869a5360027
133b050785211
141b96d55bd5d
15dc020814e1
hex7b86bd9a1f

530541550111 has 4 divisors (see below), whose sum is σ = 530546291424. Its totient is φ = 530536808800.

The previous prime is 530541550073. The next prime is 530541550171. The reversal of 530541550111 is 111055145035.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-530541550111 is a prime.

It is a super-2 number, since 2×5305415501112 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530541550171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198650 + ... + 2427991.

It is an arithmetic number, because the mean of its divisors is an integer number (132636572856).

Almost surely, 2530541550111 is an apocalyptic number.

530541550111 is a deficient number, since it is larger than the sum of its proper divisors (4741313).

530541550111 is a wasteful number, since it uses less digits than its factorization.

530541550111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4741312.

The product of its (nonzero) digits is 7500, while the sum is 31.

Adding to 530541550111 its reverse (111055145035), we get a palindrome (641596695146).

The spelling of 530541550111 in words is "five hundred thirty billion, five hundred forty-one million, five hundred fifty thousand, one hundred eleven".

Divisors: 1 114671 4626641 530541550111