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5305533404501 = 11482321218591
BaseRepresentation
bin100110100110100101001…
…1011110001010101010101
3200210012111202010020010202
41031031022123301111111
51143411213022421001
615141154533430245
71055212030564241
oct115151233612525
920705452106122
105305533404501
111766078323530
127182b849b385
132c6404401305
14144b09759421
1593020a9c96b
hex4d34a6f1555

5305533404501 has 4 divisors (see below), whose sum is σ = 5787854623104. Its totient is φ = 4823212185900.

The previous prime is 5305533404491. The next prime is 5305533404531. The reversal of 5305533404501 is 1054043355035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5305533404501 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5305533404531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241160609285 + ... + 241160609306.

It is an arithmetic number, because the mean of its divisors is an integer number (1446963655776).

Almost surely, 25305533404501 is an apocalyptic number.

It is an amenable number.

5305533404501 is a deficient number, since it is larger than the sum of its proper divisors (482321218603).

5305533404501 is a wasteful number, since it uses less digits than its factorization.

5305533404501 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 482321218602.

The product of its (nonzero) digits is 270000, while the sum is 38.

Adding to 5305533404501 its reverse (1054043355035), we get a palindrome (6359576759536).

The spelling of 5305533404501 in words is "five trillion, three hundred five billion, five hundred thirty-three million, four hundred four thousand, five hundred one".

Divisors: 1 11 482321218591 5305533404501