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53055423443 = 1123209705231
BaseRepresentation
bin110001011010010110…
…011000001111010011
312001221112010202122002
4301122112120033103
51332124142022233
640212345504215
73555522441551
oct613226301723
9161845122562
1053055423443
11205564489a0
12a3481a206b
135006a8b0a9
1427d4442bd1
1515a7c356e8
hexc5a5983d3

53055423443 has 8 divisors (see below), whose sum is σ = 60395106816. Its totient is φ = 46135150600.

The previous prime is 53055423371. The next prime is 53055423461. The reversal of 53055423443 is 34432455035.

53055423443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 53055423443 - 214 = 53055407059 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53055423397 and 53055423406.

It is not an unprimeable number, because it can be changed into a prime (53055423143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104852363 + ... + 104852868.

It is an arithmetic number, because the mean of its divisors is an integer number (7549388352).

Almost surely, 253055423443 is an apocalyptic number.

53055423443 is a deficient number, since it is larger than the sum of its proper divisors (7339683373).

53055423443 is a wasteful number, since it uses less digits than its factorization.

53055423443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 209705265.

The product of its (nonzero) digits is 432000, while the sum is 38.

Adding to 53055423443 its reverse (34432455035), we get a palindrome (87487878478).

The spelling of 53055423443 in words is "fifty-three billion, fifty-five million, four hundred twenty-three thousand, four hundred forty-three".

Divisors: 1 11 23 253 209705231 2306757541 4823220313 53055423443