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53060497333 is a prime number
BaseRepresentation
bin110001011010101001…
…101110111110110101
312001221212200112200221
4301122221232332311
51332131441403313
640213050334341
73555613533334
oct613251567665
9161855615627
1053060497333
11205592a3a98
12a349a2a3b1
135007b466ac
1427d4da3d1b
1515a83d8c8d
hexc5aa6efb5

53060497333 has 2 divisors, whose sum is σ = 53060497334. Its totient is φ = 53060497332.

The previous prime is 53060497213. The next prime is 53060497337. The reversal of 53060497333 is 33379406035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44826205284 + 8234292049 = 211722^2 + 90743^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53060497333 is a prime.

It is a super-2 number, since 2×530604973332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 53060497333.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53060497337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26530248666 + 26530248667.

It is an arithmetic number, because the mean of its divisors is an integer number (26530248667).

Almost surely, 253060497333 is an apocalyptic number.

It is an amenable number.

53060497333 is a deficient number, since it is larger than the sum of its proper divisors (1).

53060497333 is an equidigital number, since it uses as much as digits as its factorization.

53060497333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 612360, while the sum is 43.

The spelling of 53060497333 in words is "fifty-three billion, sixty million, four hundred ninety-seven thousand, three hundred thirty-three".