Base | Representation |
---|---|
bin | 110001011010101001… |
… | …101110111100111101 |
3 | 12001221212200112112111 |
4 | 301122221232330331 |
5 | 1332131441402323 |
6 | 40213050334021 |
7 | 3555613533103 |
oct | 613251567475 |
9 | 161855615474 |
10 | 53060497213 |
11 | 205592a3999 |
12 | a349a2a311 |
13 | 5007b46619 |
14 | 27d4da3c73 |
15 | 15a83d8c0d |
hex | c5aa6ef3d |
53060497213 has 2 divisors, whose sum is σ = 53060497214. Its totient is φ = 53060497212.
The previous prime is 53060497103. The next prime is 53060497333. The reversal of 53060497213 is 31279406035.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43448067364 + 9612429849 = 208442^2 + 98043^2 .
It is a cyclic number.
It is not a de Polignac number, because 53060497213 - 29 = 53060496701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53060497613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26530248606 + 26530248607.
It is an arithmetic number, because the mean of its divisors is an integer number (26530248607).
Almost surely, 253060497213 is an apocalyptic number.
It is an amenable number.
53060497213 is a deficient number, since it is larger than the sum of its proper divisors (1).
53060497213 is an equidigital number, since it uses as much as digits as its factorization.
53060497213 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 40.
The spelling of 53060497213 in words is "fifty-three billion, sixty million, four hundred ninety-seven thousand, two hundred thirteen".
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