Base | Representation |
---|---|
bin | 100110100111101100111… |
… | …1001000001011011000111 |
3 | 200210102201110221211201202 |
4 | 1031033121321001123013 |
5 | 1143431130143330341 |
6 | 15142233432013115 |
7 | 1055325464253026 |
oct | 115173171013307 |
9 | 20712643854652 |
10 | 5307940214471 |
11 | 17670a2967484 |
12 | 71886a53119b |
13 | 2c66c8c3281b |
14 | 144c9726c8bd |
15 | 9311201b79b |
hex | 4d3d9e416c7 |
5307940214471 has 2 divisors, whose sum is σ = 5307940214472. Its totient is φ = 5307940214470.
The previous prime is 5307940214461. The next prime is 5307940214519. The reversal of 5307940214471 is 1744120497035.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5307940214471 - 26 = 5307940214407 is a prime.
It is a super-3 number, since 3×53079402144713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5307940214431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2653970107235 + 2653970107236.
It is an arithmetic number, because the mean of its divisors is an integer number (2653970107236).
Almost surely, 25307940214471 is an apocalyptic number.
5307940214471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5307940214471 is an equidigital number, since it uses as much as digits as its factorization.
5307940214471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 846720, while the sum is 47.
The spelling of 5307940214471 in words is "five trillion, three hundred seven billion, nine hundred forty million, two hundred fourteen thousand, four hundred seventy-one".
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