Base | Representation |
---|---|
bin | 110001011100010100… |
… | …001001011110110101 |
3 | 12002000211011210120000 |
4 | 301130110021132311 |
5 | 1332211112040031 |
6 | 40215524301513 |
7 | 3556402616250 |
oct | 613424113665 |
9 | 162024153500 |
10 | 53088393141 |
11 | 20573017583 |
12 | a357241899 |
13 | 50108629a4 |
14 | 27d8986097 |
15 | 15aaa993e6 |
hex | c5c5097b5 |
53088393141 has 40 divisors (see below), whose sum is σ = 93557865984. Its totient is φ = 29357627040.
The previous prime is 53088393131. The next prime is 53088393143. The reversal of 53088393141 is 14139388035.
53088393141 is a `hidden beast` number, since 530 + 8 + 83 + 9 + 31 + 4 + 1 = 666.
53088393141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53088393141 - 25 = 53088393109 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53088393143) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1492590 + ... + 1527743.
Almost surely, 253088393141 is an apocalyptic number.
It is an amenable number.
53088393141 is a deficient number, since it is larger than the sum of its proper divisors (40469472843).
53088393141 is a wasteful number, since it uses less digits than its factorization.
53088393141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3020383 (or 3020374 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 45.
The spelling of 53088393141 in words is "fifty-three billion, eighty-eight million, three hundred ninety-three thousand, one hundred forty-one".
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