Base | Representation |
---|---|
bin | 110001011100100110… |
… | …011010111111010100 |
3 | 12002001011012011121122 |
4 | 301130212122333110 |
5 | 1332213323332234 |
6 | 40220215103112 |
7 | 3556461420200 |
oct | 613446327724 |
9 | 162034164548 |
10 | 53093183444 |
11 | 20575799604 |
12 | a358971a98 |
13 | 501184c1a2 |
14 | 27d9471b00 |
15 | 15ab1e392e |
hex | c5c99afd4 |
53093183444 has 36 divisors (see below), whose sum is σ = 113771115360. Its totient is φ = 21556629360.
The previous prime is 53093183443. The next prime is 53093183461. The reversal of 53093183444 is 44438139035.
It is a super-2 number, since 2×530931834442 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 53093183395 and 53093183404.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53093183443) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7124792 + ... + 7132239.
It is an arithmetic number, because the mean of its divisors is an integer number (3160308760).
Almost surely, 253093183444 is an apocalyptic number.
It is an amenable number.
53093183444 is an abundant number, since it is smaller than the sum of its proper divisors (60677931916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53093183444 is a wasteful number, since it uses less digits than its factorization.
53093183444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14257068 (or 14257059 counting only the distinct ones).
The product of its (nonzero) digits is 622080, while the sum is 44.
The spelling of 53093183444 in words is "fifty-three billion, ninety-three million, one hundred eighty-three thousand, four hundred forty-four".
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