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5310040400173 is a prime number
BaseRepresentation
bin100110101000101011100…
…0100100110000100101101
3200210122010211211022220101
41031101113010212010231
51143444430320301143
615143222054151101
71055431515452305
oct115212704460455
920718124738811
105310040400173
111767a80412043
12719155952491
132c6972087062
14145016166605
15931d65bdb4d
hex4d45712612d

5310040400173 has 2 divisors, whose sum is σ = 5310040400174. Its totient is φ = 5310040400172.

The previous prime is 5310040400113. The next prime is 5310040400233. The reversal of 5310040400173 is 3710040400135.

It is a balanced prime because it is at equal distance from previous prime (5310040400113) and next prime (5310040400233).

It can be written as a sum of positive squares in only one way, i.e., 4820492495844 + 489547904329 = 2195562^2 + 699677^2 .

It is a cyclic number.

It is not a de Polignac number, because 5310040400173 - 217 = 5310040269101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5310040400113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2655020200086 + 2655020200087.

It is an arithmetic number, because the mean of its divisors is an integer number (2655020200087).

Almost surely, 25310040400173 is an apocalyptic number.

It is an amenable number.

5310040400173 is a deficient number, since it is larger than the sum of its proper divisors (1).

5310040400173 is an equidigital number, since it uses as much as digits as its factorization.

5310040400173 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 28.

The spelling of 5310040400173 in words is "five trillion, three hundred ten billion, forty million, four hundred thousand, one hundred seventy-three".