Base | Representation |
---|---|
bin | 111100010111100100011110… |
… | …1001100011101101010111111 |
3 | 2120122010120202101012110020011 |
4 | 1320233020331030131222333 |
5 | 1024044441231404213403 |
6 | 5121204200245004051 |
7 | 216563563150155124 |
oct | 17057107514355277 |
9 | 2518116671173204 |
10 | 531005013351103 |
11 | 144215a63845695 |
12 | 4b6803b46b3627 |
13 | 19a3a7339232c5 |
14 | 951aacb9c874b |
15 | 415c9d4130a6d |
hex | 1e2f23d31dabf |
531005013351103 has 24 divisors (see below), whose sum is σ = 561467113930176. Its totient is φ = 502121221862400.
The previous prime is 531005013351083. The next prime is 531005013351181. The reversal of 531005013351103 is 301153310500135.
It is not a de Polignac number, because 531005013351103 - 237 = 530867574397631 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (531005013351403) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 648518323 + ... + 649336603.
It is an arithmetic number, because the mean of its divisors is an integer number (23394463080424).
Almost surely, 2531005013351103 is an apocalyptic number.
531005013351103 is a deficient number, since it is larger than the sum of its proper divisors (30462100579073).
531005013351103 is a wasteful number, since it uses less digits than its factorization.
531005013351103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 821663 (or 821644 counting only the distinct ones).
The product of its (nonzero) digits is 10125, while the sum is 31.
Adding to 531005013351103 its reverse (301153310500135), we get a palindrome (832158323851238).
The spelling of 531005013351103 in words is "five hundred thirty-one trillion, five billion, thirteen million, three hundred fifty-one thousand, one hundred three".
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