Base | Representation |
---|---|
bin | 110001011101000100… |
… | …110010101111011010 |
3 | 12002001201011122212221 |
4 | 301131010302233122 |
5 | 1332222343120200 |
6 | 40221101454254 |
7 | 3556616166652 |
oct | 613504625732 |
9 | 162051148787 |
10 | 53101145050 |
11 | 2057a237248 |
12 | a35b57138a |
13 | 50133a8cb5 |
14 | 27da545362 |
15 | 15abc6791a |
hex | c5d132bda |
53101145050 has 48 divisors (see below), whose sum is σ = 101265706080. Its totient is φ = 20705307840.
The previous prime is 53101145029. The next prime is 53101145057. The reversal of 53101145050 is 5054110135.
It is a happy number.
It is a super-2 number, since 2×531011450502 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is not an unprimeable number, because it can be changed into a prime (53101145057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1070089 + ... + 1118611.
It is an arithmetic number, because the mean of its divisors is an integer number (2109702210).
Almost surely, 253101145050 is an apocalyptic number.
53101145050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53101145050 is a deficient number, since it is larger than the sum of its proper divisors (48164561030).
53101145050 is a wasteful number, since it uses less digits than its factorization.
53101145050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49087 (or 49082 counting only the distinct ones).
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 53101145050 its reverse (5054110135), we get a palindrome (58155255185).
The spelling of 53101145050 in words is "fifty-three billion, one hundred one million, one hundred forty-five thousand, fifty".
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